我有数组，需要使用for循环而无需Array.reverse方法将其反转.
I have array and need to reverse it without Array.reverse method, only with a for loop.
var names:[String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"]推荐答案
这是@Abhinav的答案翻译为 Swift 2.2 :
Here is @Abhinav 's answer translated to Swift 2.2 :
var names: [String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"] var reversedNames = [String]() for arrayIndex in (names.count - 1).stride(through: 0, by: -1) { reversedNames.append(names[arrayIndex]) }使用此代码不应为您提供关于不赞成使用C样式for循环或使用--的任何错误或警告.
Using this code shouldn't give you any errors or warnings about the use deprecated of C-style for-loops or the use of --.
快捷键3-当前:
let names: [String] = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"] var reversedNames = [String]() for arrayIndex in stride(from: names.count - 1, through: 0, by: -1) { reversedNames.append(names[arrayIndex]) }或者，您可以正常遍历并每次减去:
Alternatively, you could loop through normally and subtract each time:
let names = ["Apple", "Microsoft", "Sony", "Lenovo", "Asus"] let totalIndices = names.count - 1 // We get this value one time instead of once per iteration. var reversedNames = [String]() for arrayIndex in 0...totalIndices { reversedNames.append(names[totalIndices - arrayIndex]) }