我需要我的阵列"列表数据中的最高，第二高和第三高的数字.我通过使用Collections.max()获得最大价值(最高数字).但是，我需要第二大和第三大值. 我的代码:
I need Highest,second highest and third highest number from My Array list Data. I am getting Max Value (highest number) by using Collections.max(). But, I need Second largest and third largest values. My Code:
maxPartyid = Collections.max(electionresdashlist.get(k).getPartyNamesDTO()); //1st Highest System.out.println( "maxPartyid:::"+maxPartyid); in DTO : public class PartyNamesDTO implements Comparable<PartyNamesDTO>{ private String partyId; public String getPartyId() { return partyId; } public void setPartyId(String partyId) { this.partyId = partyId; } private Integer votes; public Integer getVotes() { return votes; } public void setVotes(Integer votes) { this.votes = votes; } @Override public int compareTo(PartyNamesDTO emp) { return this.votespareTo(emp.getVotes()); } public String toString(){ return partyId; } }
推荐答案
由于您已经在PartyNamesDTO上实现了Comparable接口，因此您可以
Since you implemented the Comparable interface on PartyNamesDTO you can just do
Collections.sort(electionresdashlist)这将使您的列表根据compareTo逻辑进行排序，如果您的排序是升序，则可以获得最大记录为
which will make your list sorted according to compareTo logic and if your sorting is ascending order then you can get max record as
electionresdashlist.get(electionresdashlist.size()-1); electionresdashlist.get(electionresdashlist.size()-2); electionresdashlist.get(electionresdashlist.size()-3);，如果是降序排列，则相反.
and if it is descending order the other way around