假设我有两个数组:
$a1 = array(0,1,2); $a2 = array(3,4,5);我希望能够进行合并，使数组交替而不是合并.我想要这个结果:
I want to be able to do a merge that alternates the arrays and not concatanate them. I want this result:
array(0,3,1,4,2,5);是否存在执行此操作的本机方法，因为这里存在性能问题，因为我需要执行数千次
Is there a native way to do this as performance is an issue here since I need to do this thousands of times
请注意，我知道我可以这样做:
Please note, I know I can do it like this:
for (var $i = 0; $i < count($a1); $i++) { newArray[] = $a1[$i]; newArray[] = $b1[$i]; }我正在寻找一种内置方式，如果有一种更快的方式
I'm looking for a built in way if there is a faster one
推荐答案$count = count($a1); for ($i = 0; $i < $count; $i++) { $newArray[] = $a1[$i]; $newArray[] = $b1[$i]; }
我在这里的工作完成了.
My work here is done.
$a1 = array(0,1,2); $a2 = array(3,4,5); $start = microtime(TRUE); for($t = 0; $t < 100000; $t++) { $newArray = array(); $count = count($a1); for ($i = 0; $i < $count; $i++) { $newArray[] = $a1[$i]; $newArray[] = $a2[$i]; } } echo round(microtime(TRUE) - $start, 2); # 0.6 $a1 = array(0,1,2); $a2 = array(3,4,5); $start = microtime(TRUE); for($t = 0; $t < 100000; $t++) { $newArray = array(); for ($i = 0; $i < count($a1); $i++) { $newArray[] = $a1[$i]; $newArray[] = $a2[$i]; } } echo round(microtime(TRUE) - $start, 2); # 0.85因此，预先计数的数组大小将快约1/4 [需要引用](在freakin的100.000次迭代中，您总共将获得0.2).如果将count()放入循环内，它将在每个iteration上重新计数.在我看来，1/4似乎是一个更快的速度.如果您正在寻找编译函数，则可以停止.
So pre-counting array size will be ~1/4 [citation needed] (on freakin' 100.000 iterations you will gain 0.2 in total) faster. If you put count() inside loop, it will recount on every iteration. 1/4 seems to me a reasonably faster. If you are looking for compiled function, you can stop.
P.S.基准就像比基尼一样，它可以显示所有内容，而没有任何显示.
P.S. Benchmark is like bikini, it shows you everything, and nothing.