使用Node.js将文件系统中的目录结构转换为JSON

我有这样的文件结构：

root
|_ fruits
|___ apple
|______images
|________ apple001.jpg
|________ apple002.jpg
|_ animals
|___ cat
|______images
|________ cat001.jpg
|________ cat002.jpg

我想，使用Javascript和Node.js，监听这个根目录和所有子目录，并创建一个镜像这个目录结构的JSON，每个节点包含类型，名称，路径和子节点：

data = [
  {
    type: "folder",
    name: "animals",
    path: "/animals",
    children: [
      {
        type: "folder",
        name: "cat",
        path: "/animals/cat",
        children: [
          {
            type: "folder",
            name: "images",
            path: "/animals/cat/images",
            children: [
              {
                type: "file",
                name: "cat001.jpg",
                path: "/animals/cat/images/cat001.jpg"
              }, {
                type: "file",
                name: "cat001.jpg",
                path: "/animals/cat/images/cat002.jpg"
              }
            ]
          }
        ]
      }
    ]
  }
];

这是一个coffeescript JSON：

data = 
[
  type: "folder"
  name: "animals"
  path: "/animals"
  children  :
    [
      type: "folder"
      name: "cat"
      path: "/animals/cat"
      children:
        [
          type: "folder"
          name: "images"
          path: "/animals/cat/images"
          children: 
            [
              type: "file"
              name: "cat001.jpg"
              path: "/animals/cat/images/cat001.jpg"
            , 
              type: "file"
              name: "cat001.jpg"
              path: "/animals/cat/images/cat002.jpg"
            ]
        ]
    ]
]

如何在django视图中获取这个json数据格式？（python）

这是一个草图。错误处理留给读者练习。

var fs = require('fs'),
    path = require('path')

function dirTree(filename) {
    var stats = fs.lstatSync(filename),
        info = {
            path: filename,
            name: path.basename(filename)
        };

    if (stats.isDirectory()) {
        info.type = "folder";
        info.children = fs.readdirSync(filename).map(function(child) {
            return dirTree(filename + '/' + child);
        });
    } else {
        // Assuming it's a file. In real life it could be a symlink or
        // something else!
        info.type = "file";
    }

    return info;
}

if (module.parent == undefined) {
    // node dirTree.js ~/foo/bar
    var util = require('util');
    console.log(util.inspect(dirTree(process.argv[2]), false, null));
}