Graphql，node.js和sql，不能为非可空字段返回null

我想将数据从db返回到api。数据正在记录但未显示在graphql api上。

const express = require('express');
const bodyParser = require('body-parser');
const graphqlHttp = require('express-graphql');
const { buildSchema } = require('graphql');
var mysql = require('mysql');

const app = express();  

//start mysql connection    
var connection = mysql.createConnection({    
  host     : 'localhost', //mysql database host name    
  user     : 'root', //mysql database user name    
  password : '', //mysql database password    
  database : 'test' //mysql database name    
});

connection.connect(function(err) {    
  if (err) throw err      
})    

//end mysql connection

app.use(bodyParser.json());    
app.use(    
  '/graphql',    
  graphqlHttp({
    schema: buildSchema(`
        type users {
          id: String!
          username: String!
          password: String!
          role: String!
          name: String!
          photo: String!
        }
        type RootQuery {
            getUsers: [users!]!
        }
        type RootMutation {
          createUsers(name: String): String
        }
        schema {
            query: RootQuery
            mutation: RootMutation
        }
    `),
    rootValue: {
      getUsers: () => {
        connection.query('select * from users', function (error, results, fields) {
          if (error) throw error;
          console.log(JSON.stringify(results))
          return JSON.stringify(results) ;
        });
      },
      createUsers: (args) => {
        const eventName = args.name;
        return eventName;
      }
    },
    graphiql: true
  })
);

app.listen(3000);

结果：

query
{
  getUsers {
    id
  }  
}

OUTPUT：

{
  "errors": [
    {
      "message": "Cannot return null for non-nullable field RootQuery.getUsers.",
      "locations": [
        {
          "line": 3,
          "column": 3
        }
      ],
      "path": [
        "getUsers"
      ]
    }
  ],
  "data": null
}

这是你的解析器：

getUsers: () => {
  connection.query('select * from users', function (error, results, fields) {
    if (error) throw error;

    //users = results;
    console.log(JSON.stringify(results));
    return JSON.stringify(results) ;
  });
},

GraphQL解析器必须返回将解析为值的值或Promise。但是，在这里，你也没有回来。请记住，回调是异步调用的，因此在回调中返回值不会做任何事情（在大多数情况下）。

你真的应该使用像promise-mysql而不是mysql这样的东西，但你仍然可以使用Promise包装一个回调并返回Promise。这样的事情应该有效：

getUsers: () => {
  // Note, we have to return the Promise here
  return new Promise((resolve, reject) => {
    connection.query('select * from users', (error, results, fields) => {
      if (error) {
        reject(error)
      } else {
        // Don't stringify
        resolve(results)
      }
    })
  })
},